Originally Posted by

**Miss** 1- The following function is one-to-one

f(x)= -x if x belongs to [-1,0]

f(x)=3x+2 if x belongs to [0,1]

2- The following parametric curve represents a line segment from (0,3) to (2,0) :

$\displaystyle x(t)=2sin^2(t)$ and $\displaystyle y(t)=3cos^2(t)$ where $\displaystyle t \in [0,\frac{\pi}{2}]$

For (1): I think its false, if we draw the function on the interval [-1,1] we will get a graph which is similar to the graph of f(x)=|x| (the v-shape). clearly there are horizontal lines intersect the curve of f in more than one point, so its not 1-1 function, so the statement is false.

For (2): I do not have any idea!