1. ## Derivative sinhx*tanhx

When I calculate the derivative of

$
y = sinh(x) tanh(x)
$

I come up with

$
y' = cosh(x) tanh(x) + sinh(x) sech^2(x)
$

Should this be further simplified?

2. $cosh(x) \cdot tanh(x)=sinh(x)$

then take $sinh(x)$ as a common factor ..

3. So...

$
y' = sinh(x)(1+sech^2(x))
$

Sorry, it has been a very long time since I have had to work these sorts of problems.

4. Correct .