I have to prove that (a - b) x (a + b) = 2(a x b)
I get this:
(a + -b) x c = 2(a x b)
a x c + -b x c = 2(a x b)
a x (a + b) + -b x (a + b)= 2(a x b)
a x a + a x b + -b x a + -b x b= 2( a x b) - (a x b)
-(a x b)
0 + -b x a + -b x b = a x b
a x b + -b x b = a x b - (a x b)
-a x b
-b x b = 0
and I can't do anything
Thanks for your help
Are you saying that you are subtracting (a x b) from both sides?
There is no need to do that. Yes, you have, on the left
a x a + a x b - b x a+ b x b
But the cross product is anti-symmetric: a x a= b x b= 0 and
b x a= - a x b so
a x a+ a x b- b x a + b x b= 0+ a x b- (-a x b)+ 0= 2 a x b.
You can't do anything because you went ahead and canceled everything and arrived at the trivially true statement "-b x b = 0"!0 + -b x a + -b x b = a x b
a x b + -b x b = a x b - (a x b)
-a x b
-b x b = 0
and I can't do anything
Thanks for your help