Originally Posted by

**Paymemoney** Hi

The following question i am having problem finishing off.

1)For the function P(x) = 5x^{1.5} e^{-2x}

Find the first and second derivative, and note each point where the first and second derivative is zero. What happens at x=0?

I have found the first and second derivatives, and is the next step assigning x=0. I done this i always get 0.

$\displaystyle \frac{dy}{dx} = -10x^{\color{red}0.5\color{black}}e^{-2x}+7.5x^{0.5}e^{-2x}$

$\displaystyle \frac{d^2y}{dx^2} = 20x^{0.5}e^{-2x}-5x^{-0.5}e^{-2x}-15x^{0.5}e^{-2x}+3.75x^{0.5}e^{-2x}$

The next part is to sketch a graph of P(x) against x, noting each of the point identified in (a).

P.s