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Thread: Find any critical points and relative extrema of the function x^3 - 3xy + y^2

  1. June 2nd 2010, 08:57 AM #1
    ewkimchi
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    Find any critical points and relative extrema of the function x^3 - 3xy + y^2

    Find any critical points and relative extrema of the function x^3 - 3xy + y^2

    I got (0,0) is a saddle point, (3/2, 9/4) is a relative minimum
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  2. June 2nd 2010, 09:45 AM #2
    Soroban
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    Hello, ewkimchi!

    Find any critical points and relative extrema of: . f(x,y) \:=\:x^3 - 3xy + y^2

    I got: . (0,0) saddle point, . (\tfrac{3}{2},\,\tfrac{9}{4}) relative minimum.

    I agree!
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