Hi please help to solve this integral .
$\displaystyle
\int\sqrt{1+cos^2x}dx
$
integrate Sqrt[1 + (Cos[x])^2] - Wolfram|Alpha
Where has the integral come from?
The main question intend is to calculate the length of arc which
will create by F(x) = Sin(X) from 0 to pi .
so, we should calculate this : $\displaystyle \int\sqrt{1+y'^2}dx$
and if we put cosx instead of y' we have the above integral.
$\displaystyle \int\sqrt{1+cos^2x}dx$
Iam very Now . what is ellipitic integral ??????