Originally Posted by

**ewkimchi** Do these work?

A)

a) (99n + 1)/100n

**No, this one converges to $\displaystyle \color{blue} \frac{99}{100}$.**

b) (3n+1)/4n

**Correct.**

c) (n^3)/(n^2 + 1)

**Correct.**

B)

a)

by p series test, diverges b/c 1/3<1

**Correct.**

b)

by geometric series test, converges b/c 1/4<1 and sum=8/3

**The series in your question is 4^n not (1/4)^n !**

c)

I'm not sure about this one because 4 isn't under a fraction or does that even matter?

Anyway, I got

by geometric series test diverges b/c 4>1

**There is no part c in your question !**

**And remember that, you should check the absolute value of the common ratio.**

**For instance,**

**$\displaystyle \sum_{n=0}^{\infty} \left(\frac{-3}{2}\right)^n$ **__DIVERGES__.

**because |-3/2|=3/2>1.**