1. ## d(x/lnx) /dx

Use standard results about differentiation to find f'(x) where f(x) = x / lnx

2. Originally Posted by pasleycakes

Use standard results about differentiation to find f'(x) where f(x) = x / lnx
You should know what quotient rule is! Try applying that rule.

3. ## solved

here is the result - 1/lnx-1/lnx^2

to get the result use the rule : (u'v-uv')/v^2 where in this case u is x and v is lnx,this derivative is simple gl

4. Originally Posted by goroner
here is the result - 1/lnx-1/lnx^2

to get the result use the rule : (u'v-uv')/v^2 where in this case u is x and v is lnx,this derivative is simple gl
I'd like to know the answer too, but is the answer you just gave correct?

I mean, is $ln x^2 = (ln x)^2$

Using the quotient rule, I know that I get:

$\frac{ln x - 1}{(ln x)^2}$