Hi can anyone help please. Use standard results about differentiation to find f'(x) where f(x) = x / lnx

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Originally Posted by pasleycakes Hi can anyone help please. Use standard results about differentiation to find f'(x) where f(x) = x / lnx You should know what quotient rule is! Try applying that rule.

here is the result - 1/lnx-1/lnx^2 to get the result use the rule : (u'v-uv')/v^2 where in this case u is x and v is lnx,this derivative is simple gl

Originally Posted by goroner here is the result - 1/lnx-1/lnx^2 to get the result use the rule : (u'v-uv')/v^2 where in this case u is x and v is lnx,this derivative is simple gl I'd like to know the answer too, but is the answer you just gave correct? I mean, is Using the quotient rule, I know that I get:

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