I am trying to find divergence or convergence using Maple of;
SUM from n = 1 to inf of the equation:
(1+sin(n)/n)^2
I run it in Maple as a ratio test but when I try to take the limit, I get that the solution is undefined?
I am trying to find divergence or convergence using Maple of;
SUM from n = 1 to inf of the equation:
(1+sin(n)/n)^2
I run it in Maple as a ratio test but when I try to take the limit, I get that the solution is undefined?
My apologies.
I really need to figure out how to get the fancy equations in these postings.
The actual question is:
[(1+sin(n))/n]^2
Not:
(1+sin(n)/n)^2
Now, that probably changes things!
I agree, that in the last scenario where "1" was not part of the numerator...then it would be divergent but what if we use the new equation - again, my apologies for lack of expertise in posting the question correctly the first time.
Thanks, I assumed that since $\displaystyle \lim_{n \to \infty}\sin{n}$ doesn't exist, due to its oscillatory nature, then neither would $\displaystyle \lim_{n \to \infty}\frac{\sin{n}}{n}$.
What happens at the points where you end up with $\displaystyle \frac{0}{\infty}$ though?