Hi, I'm having a lot of trouble solving the following question related to trig differentiation. I would greatly appreciate any help.
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Originally Posted by nikhil -2(sinx)tan(cosx)[sec(cosx)]^2 Yes, I'm pretty sure thats the answer..Would you mind sharing a bit of the working?
Nikhil used the chain rule.
Let u= cos(x),[/tex]v= tan(u)[/tex], and
Then , , and
The chain rule says .
Of course, nikhil did it with specifically writing out "u", "v", and "w".
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