Hi, I'm having a lot of trouble solving the following question related to trig differentiation. I would greatly appreciate any help. 1) Differentiate Thanks
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-2(sinx)tan(cosx)[sec(cosx)]^2
Originally Posted by nikhil -2(sinx)tan(cosx)[sec(cosx)]^2 Yes, I'm pretty sure thats the answer..Would you mind sharing a bit of the working?
d/dx (tan(cosx))^2 = 2tan(cosx)[d/dx(tan(cosx))] =2tan(cosx)(sec(cosx))^2(d/dx (cosx)) =2tan(cosx)(sec(cosx))^2(-sinx) =-2(sinx)tan(cosx)(sec(cosx))^2
Nikhil used the chain rule. Let u= cos(x),[/tex]v= tan(u)[/tex], and Then , , and The chain rule says . Of course, nikhil did it with specifically writing out "u", "v", and "w".
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