Calculate the curvature of the curve given by $\displaystyle r(t)=\frac{1}{3}t^3 i+\frac{\sqrt{2}}{2}t^2j+tk$ at point t=2. I just wanted to know if these are the correct formulas ? K=||T'(t)||/||r'(t)|| T'(t)=r'(t)/||r'(t)||
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Originally Posted by JJ007 Calculate the curvature of the curve given by $\displaystyle r(t)=\frac{1}{3}t^3 i+\frac{\sqrt{2}}{2}t^2j+tk$ at point t=2. I just wanted to know if these are the correct formulas ? K=||T'(t)||/||r'(t)|| T'(t)=r'(t)/||r'(t)|| Have you compared them with the ones in yuor classnotes and textbook? What does Google turn up? etc.
Originally Posted by mr fantastic Have you compared them with the ones in yuor classnotes and textbook? What does Google turn up? etc. The textbook associates the formula with a space curve. Is that the same thing?
What is a "space curve"? How is it different from the curves you have been working with?
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