Hi

The following question i don't know why it is incorrect.

1)$\displaystyle \int_1^3 x^{x}dx$ n=4

$\displaystyle x_0 = 0$

$\displaystyle x_1 = \frac{1}{4}$

$\displaystyle x_2 = \frac{2}{4}$

$\displaystyle x_3 = \frac{3}{4}$

$\displaystyle x_4 = \frac{4}{4}$

$\displaystyle \int_0^1 x^{x} dx = \frac{1}{12}[0+4(\frac{1}{4}^{\frac{1}{4}})+2(\frac{1}{2}^{\fra c{1}{2}})+4(\frac{3}{4}^{\frac{3}{4}})+1]$

=0.70553

book's answer is 0.7889