ball thrown up with v=10m/s from a building of height 100. find max height and time taken to reach this max.
integrate to get but initially v=10 so
at max height v=0 so t=10/g
now i integrate again to get but initially s=100 so K=100
so at t=10/g, i get s= 5.1
this answer is correct but they use
can anyone show me how they got this equation?
For part b) they want the time taken to go from h=50 to h=0.
for this i used the formula above for s and solved for t wneh h-50 and 0 to get the correct answer.
in the solutions they use
and if v2 is velocity at H=0 and v1 is velocity at H=50 then
is the above obvious?im thinking,wrongly, if i start motion at v1 then f=ma gives me a=g so v=gt+K but initially v=v1 thus v=gt+v1 ??
Can i get v2=v1-gt starting with f=ma?