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Math Help - Calculating the unit normal of a plane

  1. #1
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    Calculating the unit normal of a plane

    Hi,
    I've tried to solve a problem and I was just wondering if my answer is correct or not:

    Assume three points p_1, p_2 and p_3:
    p_1 = (1,2,3)^T
    p_2 = (2,2,1)^T
    p_3 = (0,1,3)^T

    The problem is to find the unit normal of this plane.

    I take the cross product of p_1p_2 and p_1p_3, I get:

    N = -2i + 2j - k
    I find that the length of N is sqrt((-2)^2 + 2^2 + (-1)^2) = 3.

    I.e. the answer is: (-2i + 2j - k) / 3

    Is this correct?
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    Correct.
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