Thread: Partial Differentiation

Find : ∂z/∂x


My solution:


∂u/∂x = 1
∂v/∂x =
Product rule:
∂K/∂x = v(∂u/∂x) + u(∂v/∂x) =


∂z/∂x =

There is no need to make substitutions ..
Fix your function please,,

Sorry, im learning how to using Math equation...my final answer is ∂z/∂x = . Im just want to ask whether im correct or not.

To write the square root of y : \sqrt{y}
You need the product rule to differentiate the second term,,

Originally Posted by General

To write the square root of y : \sqrt{y}
You need the product rule to differetiate the second term,,

Thanks. What you mean by "the product rule to differetiate the second term".

Originally Posted by wkn0524

How can you differentiate the red one ?

Originally Posted by General

How can you differentiate the red one ?

Sorry...The question is ask to find ∂z/∂x for this question

After differentiate xcos(xy), then i get

I know,
You have:


And you want to find , Right ?

Originally Posted by General

I know,
You have:


And you want to find , Right ?

Is ∂z/∂x = ?

If same, then yes.

Yes.
They are the same.





I used the product in blue,,

Originally Posted by General

Yes.
They are the same.





I used the product in blue,,

Ouch, got the minus sign. The partial differentiation was not exactly same as differentiation topic, knew the concepts now.