Find : ∂z/∂x

My solution:

∂u/∂x = 1

∂v/∂x =

Product rule:

∂K/∂x = v(∂u/∂x) + u(∂v/∂x) =

∂z/∂x =

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- May 28th 2010, 09:47 AMwkn0524Partial Differentiation
Find : ∂z/∂x

My solution:

∂u/∂x = 1

∂v/∂x =

Product rule:

∂K/∂x = v(∂u/∂x) + u(∂v/∂x) =

∂z/∂x = - May 28th 2010, 09:55 AMGeneral
**There is no need to make substitutions ..**

**Fix your function please,,** - May 28th 2010, 09:59 AMwkn0524
Sorry, im learning how to using Math equation...my final answer is ∂z/∂x = . Im just want to ask whether im correct or not.

- May 28th 2010, 10:05 AMGeneral
**To write the square root of y : \sqrt{y}**

**You need the product rule to differentiate the second term,,** - May 28th 2010, 10:12 AMwkn0524
- May 28th 2010, 10:15 AMGeneral
- May 28th 2010, 10:18 AMwkn0524
- May 28th 2010, 10:19 AMGeneral
**I know,**

**You have:**

**And you want to find , Right ?** - May 28th 2010, 10:26 AMwkn0524
- May 28th 2010, 10:31 AMGeneral
**Yes.**

**They are the same.**

**I used the product in blue,,** - May 28th 2010, 10:36 AMwkn0524