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Thread: Integrate 1/(xln²x) with respect to x by change of variable.

  1. May 26th 2010, 08:57 AM #1
    feyomi
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    Integrate 1/(xln²x) with respect to x by change of variable.

    I'm struggling to find a suitable substitution.
    If I know one then I should be able to work it out from there.
    Thanks for any help.
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  2. May 26th 2010, 08:59 AM #2
    General
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    put u=ln(x) \implies du=\frac{dx}{x}

    So the integral will be : \int \frac{du}{u^2}=\frac{-1}{u}+C=\frac{-1}{ln(x)} + C
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