I'm struggling to find a suitable substitution. If I know one then I should be able to work it out from there. Thanks for any help.
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put $\displaystyle u=ln(x) \implies du=\frac{dx}{x}$ So the integral will be : $\displaystyle \int \frac{du}{u^2}=\frac{-1}{u}+C=\frac{-1}{ln(x)} + C$
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