Integrate 1/(xln²x) with respect to x by change of variable.

Printable View

• May 26th 2010, 09:57 AM
feyomi
Integrate 1/(xln²x) with respect to x by change of variable.
I'm struggling to find a suitable substitution.
If I know one then I should be able to work it out from there.
Thanks for any help.
• May 26th 2010, 09:59 AM
General
put $u=ln(x) \implies du=\frac{dx}{x}$

So the integral will be : $\int \frac{du}{u^2}=\frac{-1}{u}+C=\frac{-1}{ln(x)} + C$