I am stuck on the problem :

Find the Critical Numbers of F(x)= 2^(2x-5)-2^(x+1)

I differentiated and got to :

F'(x)=(ln(2)*4^x)/(16)-2ln(2)*2^x

I am not sure what to do next?

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- May 24th 2010, 06:35 PMsydewayzloccfinding critical numbers
I am stuck on the problem :

Find the Critical Numbers of F(x)= 2^(2x-5)-2^(x+1)

I differentiated and got to :

F'(x)=(ln(2)*4^x)/(16)-2ln(2)*2^x

I am not sure what to do next? - May 24th 2010, 06:48 PMharish21
A number $\displaystyle a$ in the domain of a given function $\displaystyle f$ is called a critical number of $\displaystyle f$ if $\displaystyle f '(a) = 0$ or $\displaystyle f'$ is undefined at $\displaystyle x = a$.

so, solve for $\displaystyle f'(x)=0$.

By the way, is your differentiation complete? Your answer doesn't seem correct - May 24th 2010, 07:02 PMsydewayzlocc
yes thank you I realize that a critical number is when f'(x) is 0 or undefined, and the answer I got for the derivative is what the calculator gave me for d/dx of f(x). I am just unsure how to go about solving for x with the natural logs.

- May 24th 2010, 07:28 PMharish21