You told me to post a couple more on here to make sure I had gotten this...

This one is going to prove more difficult for me.

f(x) = the 4th root of (2x+1/1-3x)....the whole fraction under the 4th root.

u(x) = the 4th root of u or u^(-1/4)

u'(x) = -1/4u^(-5/4)

v(x) = [2x+1/1-3x]

v'(x) = (1-3x)(2) - (2x+1)(-3)/(1-3x)^2

v'(x) = (2-6x) - (-6x-3)/(1-3x)^2

v'(x) = -1/(1-3x)^2

If that is correct, I will move on with

u(x) * v'(x) - v'(x) * u(x)/u(x)^2