Find nth derivative by using series.

**kientri123** · May 23rd 2010, 05:22 PM

Hi,
I got this problem from my Calculus class 's homeworks, I dont know how to solve

. Please help me, any help will be great appreciated.

1. use series to find f^6 (0) , for f(x) = sin(3x^2)

**skeeter** · May 23rd 2010, 05:34 PM

Originally Posted by kientri123

Hi,
I got this problem from my Calculus class 's homeworks, I dont know how to solve

. Please help me, any help will be great appreciated.

1. use series to find f^6 (0) , for f(x) = sin(3x^2)

$\sin{u} = u - \frac{u^3}{3!} + \frac{u^5}{5!} - \frac{u^7}{7!} + ...<br />$

**kientri123** · May 24th 2010, 05:16 PM

Originally Posted by skeeter

$\sin{u} = u - \frac{u^3}{3!} + \frac{u^5}{5!} - \frac{u^7}{7!} + ...<br />$

Oh, I got it. It's easier than I thought. Thanks you for your help

Thread: Find nth derivative by using series.