Hi, I got this problem from my Calculus class 's homeworks, I dont know how to solve . Please help me, any help will be great appreciated. 1. use series to find f^6 (0) , for f(x) = sin(3x^2)
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Originally Posted by kientri123 Hi, I got this problem from my Calculus class 's homeworks, I dont know how to solve . Please help me, any help will be great appreciated. 1. use series to find f^6 (0) , for f(x) = sin(3x^2) $\displaystyle \sin{u} = u - \frac{u^3}{3!} + \frac{u^5}{5!} - \frac{u^7}{7!} + ... $
Originally Posted by skeeter $\displaystyle \sin{u} = u - \frac{u^3}{3!} + \frac{u^5}{5!} - \frac{u^7}{7!} + ... $ Oh, I got it. It's easier than I thought. Thanks you for your help
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