but instead of f(x)=x^-2, let f(x) = x^(1/2 ) So, I did [ (x+h)^1/2 - (x)^1/2 ]/ h But im not sure how to simplify it. What would be my next step? Thanks alot
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Originally Posted by gomes but instead of f(x)=x^-2, let f(x) = x^(1/2 ) So, I did [ (x+h)^1/2 - (x)^1/2 ]/ h But im not sure how to simplify it. What would be my next step? Thanks alot wait.. now using the definition simplify this and get your proof
Originally Posted by gomes but instead of f(x)=x^-2, let f(x) = x^(1/2 ) finish it.
Thanks everyone Originally Posted by skeeter finish it. Thanks, I'm having trouble with sin(2x), i think my double angle formulae, i might be doing something wrong/missing something. Any help? Most appreciated!
Sorry, one more, im stuck
Originally Posted by gomes Sorry, one more, im stuck I'm lazy so I wont reproduce this here but look at : http://www.mash.dept.shef.ac.uk/Reso...principles.pdf If you have any questions we can answer them here
Originally Posted by AllanCuz I'm lazy so I wont reproduce this here but look at : http://www.mash.dept.shef.ac.uk/Reso...principles.pdf If you have any questions we can answer them here Thanks! i understand it, but what about for sin2x?
Originally Posted by gomes Thanks! i understand it, but what about for sin2x? where X=2x and H=2h ; which you proved before doing this.
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