http://img15.imageshack.us/img15/705/123gm.jpg

but instead of f(x)=x^-2, let f(x) = x^(1/2 )

So, I did

[ (x+h)^1/2 - (x)^1/2 ]/ h

But im not sure how to simplify it. What would be my next step? Thanks alot :)

Printable View

- May 22nd 2010, 12:01 PMgomesfunction --- derivative (help!)
http://img15.imageshack.us/img15/705/123gm.jpg

but instead of f(x)=x^-2, let f(x) = x^(1/2 )

So, I did

[ (x+h)^1/2 - (x)^1/2 ]/ h

But im not sure how to simplify it. What would be my next step? Thanks alot :) - May 22nd 2010, 12:26 PMharish21
- May 22nd 2010, 01:49 PMskeeter
- May 22nd 2010, 02:37 PMgomes
Thanks everyone :)

Thanks, I'm having trouble with sin(2x), i think my double angle formulae, i might be doing something wrong/missing something. Any help? Most appreciated!

http://img199.imageshack.us/img199/7870/qwertymj.jpg - May 22nd 2010, 02:47 PMgomes
Sorry, one more, im stuck :(

http://img38.imageshack.us/img38/4512/qweryn.jpg - May 22nd 2010, 07:07 PMAllanCuz
I'm lazy so I wont reproduce this here but look at : http://www.mash.dept.shef.ac.uk/Reso...principles.pdf

If you have any questions we can answer them here (Hi) - May 23rd 2010, 10:03 AMgomes
Thanks! i understand it, but what about for sin2x?

http://img199.imageshack.us/img199/7870/qwertymj.jpg - May 23rd 2010, 12:47 PMharish21