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Math Help - Improper Integral

  1. #1
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    Improper Integral

    The problem is:

    Determine whether the integral is divergent or convergent. If it is convergent, evaluate it.

    Since I don't know how to use the nice equation system, I'll write it in words. It is the integral of 9 divided by the 8th root of (x-5) with left bound of 5 and right bound of 9.

    I ended up with (72*4^(7/8))/7, but it's wrong. I can't for the life of me figure out why, so if anyone could post how to get the solution, that would be wonderful.
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  2. #2
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    Quote Originally Posted by Facepalm17 View Post
    The problem is:

    Determine whether the integral is divergent or convergent. If it is convergent, evaluate it.

    Since I don't know how to use the nice equation system, I'll write it in words. It is the integral of 9 divided by the 8th root of (x-5) with left bound of 5 and right bound of 9.

    I ended up with (72*4^(7/8))/7, but it's wrong. I can't for the life of me figure out why, so if anyone could post how to get the solution, that would be wonderful.
    Since you don't show how you ended up with your answer, none of us can figure out why you got it wrong either. The correct answer is here: integrate 9/(x - 5)^(1/8) from x = 5 to x = 9 - Wolfram|Alpha
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  3. #3
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    Quote Originally Posted by mr fantastic View Post
    Since you don't show how you ended up with your answer, none of us can figure out why you got it wrong either. The correct answer is here: integrate 9/(x - 5)^(1/8) from x = 5 to x = 9 - Wolfram|Alpha
    ...which, remarkably enough, is exactly the answer I got. The web system is wrong, maybe.
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