# Improper Integral

• May 21st 2010, 11:29 PM
Facepalm17
Improper Integral
The problem is:

Determine whether the integral is divergent or convergent. If it is convergent, evaluate it.

Since I don't know how to use the nice equation system, I'll write it in words. It is the integral of 9 divided by the 8th root of (x-5) with left bound of 5 and right bound of 9.

I ended up with (72*4^(7/8))/7, but it's wrong. I can't for the life of me figure out why, so if anyone could post how to get the solution, that would be wonderful.
• May 21st 2010, 11:34 PM
mr fantastic
Quote:

Originally Posted by Facepalm17
The problem is:

Determine whether the integral is divergent or convergent. If it is convergent, evaluate it.

Since I don't know how to use the nice equation system, I'll write it in words. It is the integral of 9 divided by the 8th root of (x-5) with left bound of 5 and right bound of 9.

I ended up with (72*4^(7/8))/7, but it's wrong. I can't for the life of me figure out why, so if anyone could post how to get the solution, that would be wonderful.

Since you don't show how you ended up with your answer, none of us can figure out why you got it wrong either. The correct answer is here: integrate 9&#x2f;&#x28;x - 5&#x29;&#x5e;&#x28;1&#x2f;8&#x29; from x &#x3d; 5 to x &#x3d; 9 - Wolfram|Alpha
• May 22nd 2010, 01:56 AM
Facepalm17
Quote:

Originally Posted by mr fantastic
Since you don't show how you ended up with your answer, none of us can figure out why you got it wrong either. The correct answer is here: integrate 9&#x2f;&#x28;x - 5&#x29;&#x5e;&#x28;1&#x2f;8&#x29; from x &#x3d; 5 to x &#x3d; 9 - Wolfram|Alpha

...which, remarkably enough, is exactly the answer I got. The web system is wrong, maybe.