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Math Help - Projectile Motion

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    Projectile Motion

    Find the speed and direction of a particle which , when projected form a point 15m above the horizontal ground, just clears the top of a wall 26.25 m and 30m away.

    Do not know how to figure out, as there are 2 variables, namely V and tan(theta)

    that is using Cartesian motion equation.
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    Quote Originally Posted by Lukybear View Post
    Find the speed and direction of a particle which , when projected form a point 15m above the horizontal ground, just clears the top of a wall 26.25 m and 30m away.

    Do not know how to figure out, as there are 2 variables, namely V and tan(theta)

    that is using Cartesian motion equation.
    actually, there are an infinite number of solutions depending on how one interprets

    ... just clears the top of a wall 26.25 m and 30m away.
    I'll make the assumption that this point is the highest point of the particle's trajectory.

    let v = initial velocity

    \theta = launch angle relative to the horizontal


    \Delta x = v \cos{\theta} \cdot t = 30

    \Delta y = 26.25-15 = v \sin{\theta} \cdot t - \frac{1}{2}gt^2

    since it just clears the wall, the y-component of velocity at that point is zero ...

    0 = (v\sin{\theta})^2 - 2g(26.25-15)

    solve the system of equations.
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