A ball is thrown with initial velocity 20 m/s at an angle of elevation of arctan (4/3). Suppose that the ball is thrown up a road inclined at arctan(1/5) to the horizontal. Show that the ball si about 9 m above the road when it reaches its greatest height and the time of flight is 2.72 seconds, and find, correct to the nearest tenth of a metre, the distance the ball has been thrown up the road.
I've already found out from previous parts that:
* the parabolic path of the ball has parametric equationx x=12t and y=16t-5t^2
* the horizontal range of the ball is 38.4 m
* the greatest height is 12.8 m
Consider an inclined plane of inclination α. Let a projectile be fired making an angle θ along the horizontal. Call axis along the inclined plane to be x-axis. Thus the velocity makes an angle (θ - α) along x-axis.
The time of flight is given by
Maximum height above the road is