Find the area of the surface obtained by rotating the curve about the x-axis.?

y = sqrt(2 + 2 x)

3<=x<=11

I know that the formula used for this is S =(integral from 3to11) 2*pi*y*sqrt(1+(y')^2)dy

for y' i get y'=1/( 2*sqrt(2+2x) )

once i plug in both y and y'. i get stuff because i'm not sure how it will all work out with the u-substitution and all.

can someone help? thanks!