f(x) = x^5 - 20

f'(x) = 5x^4

x2 = x1 - ( x1^5 - 20 ) / ( 5x1^4 )

x2 = 1 - ( (1)^5 - 20 ) / ( 5(1)^4 )

x2 = 1 - ( -19 / 5 )

x2 = 24 / 5

x2 = 4.08

My answer is wrong and the correct answer is 1.82056420. I used an initial approximation of x1 = 1, as no approximation was given.