An isosceles triangle of width and height 4m has a rectangle of heightand width
inside it such that the top corners are always flush to the sides of the triangle. What is the maximum area for the rectangle.
I know the area of the triangle isand have a function for the area of the rectangle in terms of
Gives me
The only help in need is another relationship between w and h so I can have the area in terms of one variable either, solve that and I will be finished.
Take the bottom-left right-angled triangle or the bottom-right one.Originally Posted by Bushy
An isosceles triangle of width and height 4m has a rectangle of height
I know the area of the triangle is
Gives me
The only help in need is another relationship between w and h so I can have the area in terms of one variable either
It's base isand it's height is
}=\frac{2h}{4-w})
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