can anyone help me with the process to the question. points i need to research rather than the answers. many thanks
The function $\displaystyle y=2(x-1)(x-4)^2$
(a) find the values of A and B
(b) what is the size of the shaded part
can anyone help me with the process to the question. points i need to research rather than the answers. many thanks
The function $\displaystyle y=2(x-1)(x-4)^2$
(a) find the values of A and B
(b) what is the size of the shaded part
$\displaystyle
$
A and B occur when y=0
$\displaystyle y=2(x-1)(x-4)^2$
$\displaystyle 0=2(x-1)(x-4)^2$
$\displaystyle
0=(x-1) $ and $\displaystyle 0=(x-4)$
Therefore...
$\displaystyle A=1$ and $\displaystyle B=4$
The Area is..
$\displaystyle \int2(x-1)(x-4)^2dx$
$\displaystyle 2\int(x-1)(x^2-8x+16)dx$
$\displaystyle 2\int(x^3-7x^2+24x-16)dx$
Limits of integration are 1 to 4