f(x) = e^-1/(2x) f(x) = e^-1/(2x)*(-1/2) f'(x) = -1/2e^1/2x is that correct?
Follow Math Help Forum on Facebook and Google+
Hello, startingover! f(x) .= .e^-1/(2x) f'(x) .= .e^-1/(2x)(-1/2) ? f'(x) .= .-1/2e^1/2x is that correct? . . . . no The exponent is: .-1/(2x) .= .-½ x^{-1} Its derivative is: .½ x^{-2} .= .1/(2x²)
View Tag Cloud