1. Critical Numbers

Find the critical numbers of the function. (Round your answers to three decimal places.)
s(t) = 3t4 + 4t3 − 6t2

2. Originally Posted by sheva2291
Find the critical numbers of the function. (Round your answers to three decimal places.)
s(t) = 3t4 + 4t3 − 6t2
EDIT: Hold on!

3. Set $s'(t)=0$.

You get (I assume by t2 you mean $t^2$ for example) $12t^3 + 12t^2 - 12t = 0$.

$t=0$ is an obvious solution...

Divide through by $12t$ to get

$t^2 + t - 1 = 0$

Solve this using standard $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ formula