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Math Help - Critical Numbers

  1. #1
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    Critical Numbers

    Find the critical numbers of the function. (Round your answers to three decimal places.)
    s(t) = 3t4 + 4t3 − 6t2
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  2. #2
    Super Member Deadstar's Avatar
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    Quote Originally Posted by sheva2291 View Post
    Find the critical numbers of the function. (Round your answers to three decimal places.)
    s(t) = 3t4 + 4t3 − 6t2
    EDIT: Hold on!
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  3. #3
    Super Member Deadstar's Avatar
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    Set s'(t)=0.

    You get (I assume by t2 you mean t^2 for example) 12t^3 + 12t^2 - 12t = 0.

    t=0 is an obvious solution...

    Divide through by 12t to get

    t^2 + t - 1 = 0

    Solve this using standard \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} formula
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