Critical Numbers

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May 18th 2010, 01:06 PM
sheva2291

Critical Numbers

Find the critical numbers of the function. (Round your answers to three decimal places.)
s(t) = 3t4 + 4t3 − 6t2
May 18th 2010, 01:21 PM
Deadstar

Quote:

Originally Posted by sheva2291

Find the critical numbers of the function. (Round your answers to three decimal places.)
s(t) = 3t4 + 4t3 − 6t2

EDIT: Hold on!
May 18th 2010, 01:23 PM
Deadstar

Set $s'(t)=0$ .

You get (I assume by t2 you mean $t^2$ for example) $12t^3 + 12t^2 - 12t = 0$ .

$t=0$ is an obvious solution...

Divide through by $12t$ to get

$t^2 + t - 1 = 0$

Solve this using standard $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ formula

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