Find the critical numbers of the function. (Round your answers to three decimal places.)

s(t) = 3t4 + 4t3 − 6t2

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- May 18th 2010, 01:06 PMsheva2291Critical Numbers
Find the critical numbers of the function. (Round your answers to three decimal places.)

s(t) = 3t4 + 4t3 − 6t2 - May 18th 2010, 01:21 PMDeadstar
- May 18th 2010, 01:23 PMDeadstar
Set $\displaystyle s'(t)=0$.

You get (I assume by t2 you mean $\displaystyle t^2$ for example) $\displaystyle 12t^3 + 12t^2 - 12t = 0$.

$\displaystyle t=0$ is an obvious solution...

Divide through by $\displaystyle 12t$ to get

$\displaystyle t^2 + t - 1 = 0$

Solve this using standard $\displaystyle \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ formula