Hi,

Trying to work this one out,

\int_0^{12} (\sin{t} + {t}), dx

The answer shows = (72 - cos12) - (0-1)

=(73-.84)

=72.16

I calculate (72-.98) - (0-1)

which equals 70.02.

Anyone willing to have a quick look and try and see where I went wrong?

Thanks