Reviewing for the final exam, forgot a couple simple rules.
To solve a limit algebraically
1. lim x -> -5 (x^2 +3x - 10) / (x + 5)
If you plug in -5 it is 0/0 so I factored the top to (x+5)(x-2) but the bottom is still 0. I wrote no limit for the answer to this problem.
2. lim x-> 3- (x)/(x^2 - 9)
Again the limit is 0/0. I factored the bottom to be (x+3)(x-3) but plugging in 3 you wind up getting a number over 0 again. Again I think the answer is no limit.
Am I forgetting something here?