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**unstopabl3** Q) A particle P is held at rest at a fixed point O and then released. P falls freely under gravity until it reaches the point A which is 1.25m below O.

(i) Find the speed of P at A and the time taken for P to reach A.

The particle continues to fall, but now its downward acceleration t seconds after passing through A is (10 − 0.3t)ms^-2

(ii) Find the total distance P has fallen, 3 s after being released from O.

I've solved part one to get...

t=0.5s and v=5ms^-1

But I'm unable to do part (ii). Don't know where to start and how to solve this. I've tried to integrate dv/dt but not getting anywhere.

Thanks!