Q) A particle P is held at rest at a fixed point O and then released. P falls freely under gravity until it reaches the point A which is 1.25m below O.
(i) Find the speed of P at A and the time taken for P to reach A.
The particle continues to fall, but now its downward acceleration t seconds after passing through A is (10 − 0.3t)ms^-2
(ii) Find the total distance P has fallen, 3 s after being released from O.
I've solved part one to get...
t=0.5s and v=5ms^-1
But I'm unable to do part (ii). Don't know where to start and how to solve this. I've tried to integrate dv/dt but not getting anywhere.