Originally Posted by

**orendacl** n!(x+3)^n

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4^n

I do all the work, and come up with some ridiculous fraction:

(n+1)(1/16)^n*|x+3|

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4

Take limit as n-> inf and I get zero?

I used maple as well to check and it gets:

(n+1)!(x+3)^(n+1)*4^n

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4^(n+1)*n!(x+3)

= 1/4|(x+3)(n+1)|

take limit and it becomes infinite.

Which is right?

note:

I did not show all my steps. i used the ratio test on the original problem and as you guys know, replace all n with n+1, times by reciprocal of fraction etc, You then get what i have above. I used a calculator for mine, and then tried to duplicate it with maple but get two different answers. What I need to do is find the radius of convergence.