Originally Posted by
orendacl n!(x+3)^n
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4^n
I do all the work, and come up with some ridiculous fraction:
(n+1)(1/16)^n*|x+3|
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4
Take limit as n-> inf and I get zero?
I used maple as well to check and it gets:
(n+1)!(x+3)^(n+1)*4^n
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4^(n+1)*n!(x+3)
= 1/4|(x+3)(n+1)|
take limit and it becomes infinite.
Which is right?
note:
I did not show all my steps. i used the ratio test on the original problem and as you guys know, replace all n with n+1, times by reciprocal of fraction etc, You then get what i have above. I used a calculator for mine, and then tried to duplicate it with maple but get two different answers. What I need to do is find the radius of convergence.