Planar Intersections-Please help

Find the equation of the plane that passes through the line of intersection of the planes x - 3y - 2z - 1 = 0 and 2x + 4y + z - 5 = 0 and parallel to the x-axis.

Find the line of intersection for the two planes:

1: 0t 3𝑦 − 2𝑧 − 1 = 0

2: 2𝑥 + 4𝑦 + 𝑧 − 5 = 0

let 𝑥=𝑡 (a scalar)

0𝑡+3𝑦 − 2𝑧 − 1 = 0…(1)

2𝑡 + 4𝑦 + 𝑧 − 5 = 0.….(2)

use substitution to find the value of y from equation (1):

0𝑡+3𝑦 − 2𝑧 − 1 = 0…………..(1)

3𝑦= 2𝑧+ 1

𝑦=2𝑧+13………(3)

eliminate the variable y from the equations:

First Multiply equation (1) by 4, and multiply equation (2) by -3:

0𝑡+12𝑦 −8𝑧 − 4 = 0

−6𝑡−12𝑦−3𝑧+15 = 0

Use the elimination method:

0𝑡+12𝑦 −8𝑧 − 4 = 0

−6𝑡−12𝑦−3𝑧+15 = 0

−6𝑡−11𝑧+11=0

−6𝑡−11𝑧=−11…(4)

−11𝑧=−11+6𝑡

𝑧=−6𝑡/11+1

y:

Substitute the value of z into equation (3):

𝑦=2𝑧+13

𝑦=2(−6𝑡/11+1)

𝑦=(−4𝑡−11)/11

I am very confused by the decimal values...Does my working make sense? I would appreciate any help