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Math Help - zero position

  1. #1
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    zero position

    Lef f'' > 0 on [a,b] with f(a) < 0 = f(c) < f(b), \quad \int_a^b f(x)dx = 0
    Show that c-a > b-a
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  2. #2
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    misread the problem
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  3. #3
    Junior Member autumn's Avatar
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    Quote Originally Posted by elim View Post
    Lef f'' > 0 on [a,b] with f(a) < 0 = f(c) < f(b), \quad \int_a^b f(x)dx = 0
    Show that c-a > b-a
    c-a>b-a is just c>b, but b is the right endpoint
    So this seems wrong.
    maybe c-a>b-c?
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  4. #4
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    Quote Originally Posted by autumn View Post
    c-a>b-a is just c>b, but b is the right endpoint
    So this seems wrong.
    maybe c-a>b-c?
    You are right, sorry about the typo
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