# zero position

• May 15th 2010, 11:37 AM
elim
zero position
Lef $f'' > 0$ on $[a,b]$ with $f(a) < 0 = f(c) < f(b), \quad \int_a^b f(x)dx = 0$
Show that $c-a > b-a$
• May 15th 2010, 02:14 PM
HallsofIvy
• May 15th 2010, 08:49 PM
autumn
Quote:

Originally Posted by elim
Lef $f'' > 0$ on $[a,b]$ with $f(a) < 0 = f(c) < f(b), \quad \int_a^b f(x)dx = 0$
Show that $c-a > b-a$

c-a>b-a is just c>b, but b is the right endpoint
So this seems wrong.
maybe c-a>b-c?
• May 15th 2010, 10:42 PM
elim
Quote:

Originally Posted by autumn
c-a>b-a is just c>b, but b is the right endpoint
So this seems wrong.
maybe c-a>b-c?

You are right, sorry about the typo