Integration...Please check my solution

**alireza6485** · May 14th 2010, 09:25 AM

Hi ,
Could you please help me with Integration : [sec sqrt(x)]^2 / 2 sqrt (x) ( 1+[tan sqrt(x)]^2]

First i simplified it :
sec sqrt(x)]^2 is equivalent to 1+[tan sqrt(x)]^2] I cancel them out.
1/2 sqrt(x) would remain.
Then the integration is equal to :
1/2 Integral x^ -1/2
The final answer is :
( x^1/2)
Please let me know if my answer is correct.
I would really appreciate it if you show me the correct solution.

**Soroban** · May 14th 2010, 10:27 AM

Hello, alireza64851

$\int \frac{\sec^2\!\sqrt{x} }{2\sqrt{x}(1+\tan^2\!\sqrt{x})}\,dx$

First i simplified it :

. . $\sec^2\!\sqrt{x} \:=\:1+\tan^2\!\sqrt{x}$ . . . I cancelled them out.

Then: . $\frac{1}{2\sqrt{x}}$ would remain.

Then the integration is equal to: . $\tfrac{1}{2}\int x^{-\frac{1}{2}}dx$

The final answer is: . $x^{\frac{1}{2}} + C$

Please let me know if my answer is correct.

Absolutely correct! . . . Nice work!

Thread: Integration...Please check my solution

LinkBack

Thread Tools

Display

Integration...Please check my solution

Similar Math Help Forum Discussions

Could someone check to see if my solution is correct

could some check solution please

Check my limits Solution

Very helpful sites : Check ur solution on differentiation and integration

Very helpful sites : Check ur solution on differentiation and integration

Search Tags