Could you please help me with Integration : [sec sqrt(x)]^2 / 2 sqrt (x) ( 1+[tan sqrt(x)]^2]
First i simplified it :
sec sqrt(x)]^2 is equivalent to 1+[tan sqrt(x)]^2] I cancel them out.
1/2 sqrt(x) would remain.
Then the integration is equal to :
1/2 Integral x^ -1/2
The final answer is :
Please let me know if my answer is correct.
I would really appreciate it if you show me the correct solution.