I need to check if the next infinite series convergent: Sigma (k=2-->inf) 1/{ln(k)}^a (when a real positive number) Thank you.
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Is... ... no matter which is , so that... Kind regards
Originally Posted by chisigma Is... ... no matter which is , so that... Kind regards This is not helping me, I can't use the limit test: lim(n-->inf) an/bn =L when 0<L<inf thet u can say something about the series...
Use simple comparsion. For all .
The expression means that exists a so that for any is . Now the series diverges so that the series also diverges... Kind regards
Originally Posted by Plato Use simple comparsion. For all . For Plato, how can I prove this? Thank you...
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