Find lim x -> 0+ (x^x^2)
I havent really understood indeterminate powers and how you could use natural logs or an exponential (e) to solve it. Could someone please explain using both these methods for this question?
It is not fully clear what function you mean... in both case however the limit is the same...
$\displaystyle \lim_{x \rightarrow 0+} (x^{x})^{2} = \lim_{x \rightarrow 0+} e^{2 x \ln x} = 1$
$\displaystyle \lim_{x \rightarrow 0+} x^{(x^{2})} = \lim_{x \rightarrow 0+} e^{x^{2} \ln x} = 1$
Kind regards
$\displaystyle \chi$ $\displaystyle \sigma$