Results 1 to 6 of 6

Math Help - Rolles Theorem

  1. #1
    Junior Member
    Joined
    Apr 2010
    Posts
    53

    Rolles Theorem

    I am having trouble with this problem

    Use a graphing utility to graph the function on the closed interval [a, b].
    f (x) =(x/2)-sin(pi*x/6) [−1, 0]

    Determine whether Rolle's Theorem can be applied to f on the interval.
    If Rolle's Theorem can be applied, find all values of c in the open interval (a, b) such that f '(c) = 0. (Enter your answers as a comma-separated list. Round your answers to four decimal places. If not possible, enter IMPOSSIBLE.)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Mar 2010
    From
    Florida
    Posts
    3,093
    Thanks
    5
    Right skewed arc. Just graph it with a calculator if you wan to see it.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor
    Joined
    Mar 2010
    From
    Florida
    Posts
    3,093
    Thanks
    5
    Quote Originally Posted by sydewayzlocc View Post
    can you explain why it doesnt work
    \frac{dy}{dx}\bigg[\frac{x}{2}-sin\bigg(\frac{\pi x}{6}\bigg)\bigg]=\frac{1}{2}-\frac{\pi cos\big(\frac{\pi x}{6}\big)}{6}

    Set equal to 0

    \frac{1}{2}-\frac{\pi cos\big(\frac{\pi x}{6}\big)}{6}=0\rightarrow x=\frac{6arccos\big(\frac{3}{\pi}\big)}{\pi}
    Last edited by dwsmith; May 13th 2010 at 09:11 PM. Reason: Calculator issue
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member
    Joined
    Apr 2010
    Posts
    53
    Quote Originally Posted by dwsmith View Post
    Still doesn't work.
    this still doesnt make sense, i tried saying that it was impossible and it said wrong answer, I need more help with this problem
    Follow Math Help Forum on Facebook and Google+

  5. #5
    MHF Contributor
    Joined
    Mar 2010
    From
    Florida
    Posts
    3,093
    Thanks
    5
    f'(c)=0

    \frac{1}{2}-\frac{\pi cos\big(\frac{\pi x}{6}\big)}{6}=0\rightarrow x=\frac{6arccos\big(\frac{3}{\pi}\big)}{\pi}
    Last edited by dwsmith; May 13th 2010 at 09:10 PM.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by sydewayzlocc View Post
    I am having trouble with this problem

    Use a graphing utility to graph the function on the closed interval [a, b].
    f (x) =(x/2)-sin(pi*x/6) [−1, 0]

    Determine whether Rolle's Theorem can be applied to f on the interval.
    If Rolle's Theorem can be applied, find all values of c in the open interval (a, b) such that f '(c) = 0. (Enter your answers as a comma-separated list. Round your answers to four decimal places. If not possible, enter IMPOSSIBLE.)
    What trouble are you having? Drawing the graph with a graphing utility? Do you know what Rolles Theorem says? Are you having trouble:

    Determining if Rolles Theorem can be applied? (Can you evaluate f(-1)? Can you evaluate f(0)? Can you see whether or not f is continuous over the given interval?) Can you differentiate f? Can you solve the resulting equation f'(x) = 0?

    It is no good saying "I'm having trouble". You need to show what you've been able to do and then say where you're having trouble.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Rolles Theorem
    Posted in the Differential Geometry Forum
    Replies: 2
    Last Post: March 31st 2011, 11:00 PM
  2. Rolles Theorem
    Posted in the Calculus Forum
    Replies: 15
    Last Post: April 1st 2010, 11:53 AM
  3. Rolles Theorem
    Posted in the Calculus Forum
    Replies: 4
    Last Post: March 29th 2010, 03:47 PM
  4. Rolles Theorm
    Posted in the Calculus Forum
    Replies: 1
    Last Post: March 25th 2010, 05:06 PM
  5. Zero's of polynomial [Rolles Theorem]
    Posted in the Differential Geometry Forum
    Replies: 1
    Last Post: February 25th 2010, 06:37 AM

Search Tags


/mathhelpforum @mathhelpforum