# Thread: Location of a Centroid

1. ## Location of a Centroid

I'm not really sure where to begin with this one. Any help would be greatly appreciated.

2. Originally Posted by aPexDrifta
I'm not really sure where to begin with this one. Any help would be greatly appreciated.

$\bar{y} = \frac{y}{2}$

$dA = y \, dx$

$y_c = \frac{\frac{1}{2} \int_0^b y^2 \, dx}{\int_0^b y \, dx}$

where $y = H\sin\left(\frac{\pi x}{b}\right)$

3. Thank you, that's exactly what I needed. It makes much more sense now