I'm not really sure where to begin with this one. Any help would be greatly appreciated.
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Originally Posted by aPexDrifta I'm not really sure where to begin with this one. Any help would be greatly appreciated. $\displaystyle \bar{y} = \frac{y}{2}$ $\displaystyle dA = y \, dx$ $\displaystyle y_c = \frac{\frac{1}{2} \int_0^b y^2 \, dx}{\int_0^b y \, dx}$ where $\displaystyle y = H\sin\left(\frac{\pi x}{b}\right) $
Thank you, that's exactly what I needed. It makes much more sense now
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