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Thread: Partial derivative problem

  1. #1
    Member Em Yeu Anh's Avatar
    Joined
    Nov 2009
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    94

    Red face Partial derivative problem

    I have repeated this one several times, and keep getting the same answer. But it's marked wrong, can't find my error:

    $\displaystyle w = xe^{\frac{y}{z}} $

    $\displaystyle x = t^4 $
    $\displaystyle y = 6 - t $
    $\displaystyle z = 1 + 5t $

    $\displaystyle \frac{dw}{dt} = e^{\frac{y}{z}}(4t^3) + xe^{\frac{y}{z}}(\frac{1}{z})(-1) + xe^{\frac{y}{z}}(\frac{-y}{z^2})(5) $

    $\displaystyle \frac{dw}{dt} = e^{\frac{y}{z}}(4t^3-\frac{x}{z}-\frac{5xy}{z^2}) $



    If anyone can explain what I have done wrong, I'd be extremely thankful
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  2. #2
    Senior Member
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    Your answer looks correct. What makes you think it's not? Remember, books contain misprints and professors can be wrong!
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