Thread: Differential Calculus

Could anyone please help me with this sum????

let f(x) = x/x - 3 (x is not equal to 3)

1.Show that the curve f(x) has no points of inflection.
2.Find the equations of the asymtotes of the curve y = f(x)

AND THE MOST IMPORTANT!!!

3. If the tangents to the curve at (x1, y1) and (x2, y2) are parallel, show that x1 + x2 = 6 (x1 is not equal to x2)

1. f(x) = x/x - 3 (x is not equal to 3)

take the
first derivative we get f '(x)= -3/(x-3)^2
the second derivative f'' (x) = 6/(x-3)^3
since the f''(x) no root, so f(x) no inflection point.