Ch 2.7 #10
The problem is: consider a rectangle in the xy plane, with corners at (0,0), (a,0), (0,b), (a,b). If (a,b) lies on the graph of the equation y=30-x, find a and b such that the area of the rectangle is maximized.
What I got:
A=xy y=30-x so A=x(30-x) = 30x-x^2
Is this correct?